2[y-1]+4y=3[y-1]+7

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Solution for 2[y-1]+4y=3[y-1]+7 equation:


Simplifying
2[y + -1] + 4y = 3[y + -1] + 7

Reorder the terms:
2[-1 + y] + 4y = 3[y + -1] + 7
[-1 * 2 + y * 2] + 4y = 3[y + -1] + 7
[-2 + 2y] + 4y = 3[y + -1] + 7

Combine like terms: 2y + 4y = 6y
-2 + 6y = 3[y + -1] + 7

Reorder the terms:
-2 + 6y = 3[-1 + y] + 7
-2 + 6y = [-1 * 3 + y * 3] + 7
-2 + 6y = [-3 + 3y] + 7

Reorder the terms:
-2 + 6y = -3 + 7 + 3y

Combine like terms: -3 + 7 = 4
-2 + 6y = 4 + 3y

Solving
-2 + 6y = 4 + 3y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-3y' to each side of the equation.
-2 + 6y + -3y = 4 + 3y + -3y

Combine like terms: 6y + -3y = 3y
-2 + 3y = 4 + 3y + -3y

Combine like terms: 3y + -3y = 0
-2 + 3y = 4 + 0
-2 + 3y = 4

Add '2' to each side of the equation.
-2 + 2 + 3y = 4 + 2

Combine like terms: -2 + 2 = 0
0 + 3y = 4 + 2
3y = 4 + 2

Combine like terms: 4 + 2 = 6
3y = 6

Divide each side by '3'.
y = 2

Simplifying
y = 2

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